Introduction to Higher Mathematics – Lecture 1: Problem Solving 101
Welcome to Introduction to Higher Mathematics! In this video you’ll see what this course will entail. You’ll also learn about some problem solving techniques…
Video Rating: 4 / 5
Also my main interests are music and philosophy so here is one for you to
ponder:
Given that the human mind is infinite – is maths?
I’m not sure what you used to change your voice to subtitles – but you
should have a look – it says you are an aspiring polygraph and before this
that you want to introduce us to the beauty and arsonists of
mathematics…lol.
Of course I am being picky – I know voice to text by a computer is not 100%
perfect – in fact these anomalies are quite amusing.
Also I would say the intro music is excellent – what is it?
Further good luck in your dream to teach Uni level maths if that is what it
still is.
Good video.
I actually got the answer right on the ”hole” problem. Hell yeah!
Nice 😀
SPOILER! if you want to solve where the n(n+1)/2 formula DON’T read!
alright, here we go: one day when he was a boy, Gauss were challenged to
add 1+2+3…+99+100 by his math teacher, Gauss solved that problem using
arithmetic progression properties, because if you add the An term with the
A1 in any arithmetic progression, you will get the same thing as A(n-1) +
A2 wich is the same thing as A(n-2) + A3 and so on…
Hello Bill,
One quick question on implies operator ==>
Why T ==> T is F, why not T? I did not understand the idea behind ==>
definition here
similarly
why
T ==> F , F==>T and F==>F has the values they have?
Please help me understand!!!
I actually came with a different formula for the “Stair Problem”:
1 Step: ((1 * 1) – 0) = 1
2 Step: ((2 * 2) – 1) = 3
3 Step: ((3 * 3) – 3) = 6
4 Step: ((4 * 4) – 6) = 10
5 Step: ((5 * 5) – 10) = 15
n Step = ((n * n) – p), where “p” is the previous number of blocks.
Hello Bill,
I am from Computer Science background.
Do you think i can consider this course as mathematics for Computer Science.
Basically to crack google & amazon interviews? Becasue they need problem
solving guys in software field.
Sham
This fine gentleman Bill Shillito hits the nail on the head when he says
computation exercises are NOT true math problems. These videos are great to
watch, I highly recommend watching these for both beginners and experts.
Totally on my nieces account… I’m actually trying to figure out the
dog/pens question. All that was given was the number 64. How do you find
20/12 cm? Since I am assuming that the other option was 16/16 (From the
previous slide) Haven’t been in school for 10 years and I really want to go
back for paramedic. So help is grateful. Thanks!
Excellent. Thanks so much for creating this. Truly thought provoking.
This video and the previous ones I’ve watched on this channel are
comprehensive, and engaging. I can gauge your personality in these videos.
That’s awesome! Great Job and Thank you!!!
I am like this too, Bill; determined to find my “everything”… Thank you
for taking the time to do this with STYLE. Namaste!
these videos helped me so much thanks Bill keep up the great work
Hello Bill
Adding to my previous update,
I like your course compared to MIT’s 6.042 course, because it is so
concise,precise and well presented.
Sham
Good vid. Subscribed
i wish my math professors made the subject this fun. i got interested in
math after completing my gen ed math class in college and after a remedial
course( dont laugh, lol, im dyslexic and came from a notoriously bad hs- i
think im one of only like 30 grads to go to college:P). it was kinda hard
learning to read when i first started school(i didnt learn how to read till
2nd grade and when i did i was reading at a 12th grade lvl by 3rd grade)
never thought i would figure out math, feels good haha.
@Baxter: Formula comes from this thought
So you have to sum:
1+2+3+…+(n-2)+(n-1)+n
Let’s assume you have to count twice each number (which is the same as 2
times the original sum):
1+1+2+2+3+3+…+(n-2)+(n-2)+(n-1)+(n-1)+n+n
And after rearranging numbers:
1+ 2 + 3 +…+(n-2)+(n-1)+n
+n+(n-1)+(n-2)+…+ 3 + 2 +1
*___________________________*
=(n+1)+(n+1)+(n+1)+…+(n+1)+(n+1)+(n+1)
=n(n+1)
Granted that n(n+1) is two times the original sum (because we added twice
each number, then the formula we are looking for is:
(n(n+1))/2
I’m trying to “like” mathematics by studying it once in a while, even
though my university major(nursing/premed) doesn’t require a lot of it(just
basically in chemistry related classes). These videos are helping me a lot
to get a re-introduction to what i’ve studied in high school but somehow i
can’t remember any of that, just slight glimpses like the quadratic formula
and bhaskara’s formula lol Thanks for posting these videos!!
These are brilliant!
Thank you very much – this is a great introduction. People like yourself
make a big difference to people like myself who are trying to learn maths.
I also used Herbert Gross and njwildberger videos which id also highly
recommend. Great Stuff!.
Count carefully. There are 16.
Thank you, I hope you continue this course.
Thank you for a very informative start to understanding higher mathematics.
you will be a very good teacher